# NIELIT 2019 Feb Scientist D - Section D: 19

45 views

If $x= \frac{\sqrt{p^{2}+q^{2}}+\sqrt{p^{2}-q^{2}}}{{\sqrt{p^{2}+q^{2}}-\sqrt{p^{2}-q^{2}}}}$ then $q^{2}x^{2}-2p^{2}x+q^{2}$ equals to :

1. $3$
2. $-1$
3. $-2$
4. $0$

recategorized

## Related questions

1
71 views
sum of roots of the equation $\dfrac{3x^{3}-x^{2}+x-1}{3x^{3}-x^{2}-x+1}=\dfrac{4x^{3}-7x^{2}+x+1}{4x^{3}+7x^{2}-x-1}$ is : $0$ $1$ $-1$ $2$
2
64 views
If ${m_1}$ and ${m_2}$ are the roots of equation $x^{2}+(\sqrt{3}+2)x+\sqrt{3}-1=0$ then area of the triangle formed by the lines $y={m_1}x, \: \: y={m_2}x, \: \: y=c$ is: $\bigg(\dfrac{\sqrt{33}+\sqrt{11}}{4}\bigg) c^{2}$ $\bigg( \dfrac{\sqrt{32}+\sqrt{11}}{16}\bigg ) c$ $\bigg (\dfrac{\sqrt{33}+\sqrt{10}}{4} \bigg ) c^{2}$ $\bigg( \dfrac{\sqrt{33}+\sqrt{21}}{4} \bigg) c^{3}$
A man invests some money partly in $3\%$ stock at $96$ and partly in $4\%$ stock at $120$. To get equal dividends from both, he must invest the money in the ratio : $16 : 25$ $4 : 3$ $4 : 5$ $3 : 5$
In a swimming-pool $90$ m by $40$ m, $150$ men take a dip. If the average displacement of water by a man is $8$ cubic metres, what will be rise in water level ? $30$ cm $33.33$ cm $20.33$ cm $25$ cm
A conical tent is to accommodate $10$ persons. Each person must have $6$ $m$^{2}$space to sit and$30m$^{2}$ of air to breath. What will be height of cone ? $37.5$ $m$ $150$ $m$ $75$ $m$ $15$ $m$